20b^2+b=12

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Solution for 20b^2+b=12 equation:


Simplifying
20b2 + b = 12

Reorder the terms:
b + 20b2 = 12

Solving
b + 20b2 = 12

Solving for variable 'b'.

Reorder the terms:
-12 + b + 20b2 = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + b + 20b2 = 0

Factor a trinomial.
(-4 + -5b)(3 + -4b) = 0

Subproblem 1

Set the factor '(-4 + -5b)' equal to zero and attempt to solve: Simplifying -4 + -5b = 0 Solving -4 + -5b = 0 Move all terms containing b to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -5b = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -5b = 0 + 4 -5b = 0 + 4 Combine like terms: 0 + 4 = 4 -5b = 4 Divide each side by '-5'. b = -0.8 Simplifying b = -0.8

Subproblem 2

Set the factor '(3 + -4b)' equal to zero and attempt to solve: Simplifying 3 + -4b = 0 Solving 3 + -4b = 0 Move all terms containing b to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -4b = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -4b = 0 + -3 -4b = 0 + -3 Combine like terms: 0 + -3 = -3 -4b = -3 Divide each side by '-4'. b = 0.75 Simplifying b = 0.75

Solution

b = {-0.8, 0.75}

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